In a floor plan, the length, l, of a rectangular room is twice its width, w. the perimeter of the room must be greater than 72 feet. which inequality can be used to find all possible widths of the room, in feet?

The value value of possible width of the room is 13 feet  .

Step-by-step explanation:

Given as :

The length of a rectangular room is twice its width

Let the measure of width of room =  w feet

So, The length measure = 2 time w

I,e  L = 2 × w

Now,

Let The perimeter of rectangle = P feet

∵ Perimeter of rectangle = 2 × Length + 2 × width

Or,  P = 2 × L + 2 × w

Or,  P = 2 × 2 × w + 2 × w

Or, P = 4 × w + 2 × w

Or, P = 6 × w

Now, According to question

Perimeter must be greater than 72 feet

So , from equation P = 6 × w

if w = 12 ,  then  P = 6 × 12 = 72 feet

If w = 13 ,  then  p = 6 × 13 = 78 feet

And for width = 13  ,  Length =  2 × 13 = 26

So, Perimeter = 2 × 26 + 2 × 13

or,  P = 52 + 26 = 78

So, For width = 13 feet , the statement and equation satisfy

Hence The value value of possible width of the room is 13 feet  . Answer

step-by-step explanation:

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