From a survey involving 1,000 university students, a market research company found that 710 students owned laptops, 470 owned cars, and 320 owned cars and laptops. if a university student is selected at random, what is each (empirical) probability?
(a) the student owns either a car or a laptop
(b) the student owns neither a car nor a laptop.

(A) 0.86

(B) 0.14

Step-by-step explanation:

Given : Total university students n(S)= 1,000

Number of students owned laptops n(L)= 710

Number of students owned cars n(C)= 470

Number of students owned laptops and cars n(L∩C)= 320

Then, the number of students owned either a car or a laptop :

n(L∪C)=n(L)+n(C)-n(L∩C)

=710+470-320=860

Probability that the student owns either a car or a laptop :-

Probability that the student owns neither a car nor a laptop :-

could

step-by-step explanation:

u send me a picture of ur work

first one because it can't have a fraction in it

step-by-step explanation: