Abowl in the shape of a hemispere is filled with water to a depth h=3 inches. the radius of the bowl is r inches. express the radius of the bowl r as a function of the angle theta.

The radius of the bowl R as a function of the angle theta is

Solution:

The figure is attached below

If we consider the centre of hemisphere be A

The radius be AC and AD

According to question,  

A bowl in the shape of a hemispere is filled with water to a depth h=3 inches .i.e. BC = h = 3 inches

And radius of the bowl is R inches .i.e. R = AD =AC

Now , using  trigonometric identities in triangle ABD we get

Since , AC = AB + BC

R = R Sinθ + 3

R - R Sinθ = 3

R (1 – Sinθ ) = 3

Which is the required expression for the radius of the bowl R as a function of the angle theta

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4