For each of the following scenarios state whether h0 should be rejected or not. state any assumptions that you make beyond the information that is given.
(a) h0 : µ = 4, h1 : µ 6= 4, n = 15, x = 3.4, s = 1.5, α = .05.
(b) h0 : µ = 21, h1 : µ < 21, n = 75, x = 20.12, s = 2.1, α = .10.
(c) h0 : µ = 10, h1 : µ 6= 10, n = 36, p-value = 0.061.

a) , n = 15 , X=3.4 , S=1.5 , α = .05

Formula :

p- value = 0.607(using calculator)

α = .05

p- value > α

So, we failed to reject null hypothesis

b) , n =75 , X=20.12 , S=2.1 , α = .10

Formula :

p- value = 0.000412(using calculator)

α = .1

p- value< α

So, we reject null hypothesis

(c) , n = 36, p-value = 0.061.

Assume α = .05

p-value = 0.061.

p- value > α

So, we failed to reject null hypothesis

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )