Aball is thrown vertically upward from the ground with an initial velocity of 109 ft/sec. use the quadratic function
h(t) = -16t2 + 109t to find how long it will take for the ball to reach its maximum height, and then find the maximum
height. round your answers to the nearest tenth.

Time taken by the ball to reach its maximum height is 3.4 sec

maximum height reached by the ball is 185.6ft

Step-by-step explanation:

h(t) = -16 + 109t

height is maximum ⇔ (h) = 0 and (h) < 0

(h) = 0 ⇒ -32t + 109 = 0

⇒t = ⇒ t = 3.4sec

(h) = -32 < 0

∴h(t) is maximum at t = 3.4

and maximum height is h(3.4) = -16× + 109×3.4 ⇒ h = 185.6ft

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

she will most likely have 33  

step-by-step explanation: