Two square carpets are used in the reception area of a hotel. the sum of the areas of the carpet is 941 square feet. the difference of the areas of the carpets is 741 square feet. find the dimensions of each carpet.

the dimensions are 10 and 29

Step-by-step explanation:

Let x represent the length of one square carpet.

Let y represent the length of the other square carpet.

Area of one square carpet = x^2

Area of the other square carpet = y^2

The sum of the areas of the carpet is 941 square feet. It means that

x^2 + y^2 = 941 - - - - - - - -1

The difference of the areas of the carpets is 741 square feet. It means that

x^2 - y^2 = 741 - - - - - - - - -2

Subtracting equation 2 from equation 1, it becomes

2y^2 = 200

y^2 = 200/2 = 100

Taking square root of the left hand side and right hand side of the equation, it becomes

y = √100

y = 10

Substituting y = 10 into equation 1, it becomes

x^2 + 10^2 = 941

x^2 + 100 = 941

x^2 = 941 - 100 = 841

Taking square root of the left hand side and right hand side of the equation, it becomes

x = √841 = 29

step-by-step explanation:

i believe the answer is letter c) 8

step-by-step explanation: