For our class trip. 130 tickets were purchased. the cost of a faculty ticket was to
cost of a faculty ticket was $16,500. the
cost of a student ticket was $9.900. a total of $ 1,570.800 was collected. algebraically.
determine how many faculty and how many student tickets were sold.

43 faculty tickets and 87 student tickets

Step-by-step explanation:

Let x be the number of faculty tickets sold and y be the number of student tickets sold.

130 tickets were purchased, so

x + y = 130

The cost of faculty ticket was $16.50, then x tickets cost $16.50x.

The cost of student tickets sold was $9.90, then y tickets cost $9.90y.

A total of $ 1,570.80 was collected, thus

16.50x + 9.90y = 1,570.80

You get the system of two equations:

From the first equation:

Substitute it into the second equation:

43 faculty tickets and 87 student tickets

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

.24

step-by-step explanation:

the probability is   .24

the first player had the highest probability of getting a silver marble

the game could be made fair by adding back the marble that was drawn after each draw