On the river current a canoe traveled 30 km in 3 hours and 20 min, against the current the canoe traveled 28 km in 4 hours. how far will the canoe go in 1.5 hours on the lake?

12 km

Step-by-step explanation:

Let

x km/h = speed of the canoe on the lake

y km/h = speed of the current

With the current:

Speed = x + y km/h

Distance = 30 km

Time = 3 hours 20 minutes = hours

Thus,

Against the current:

Speed = x - y km/h

Distance = 28 km

Time = 4 hours

Thus,

Add these two equations:

On the lake:

Time = 1.5 hours

Speed = 8 km/h

Distance

0

step-by-step explanation:

you can not divide by 0 so 4 ÷ 0 would be 0

0 × 9999 =0

mark brainliest   : )

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1