Acompany deposits $25,000 in a bank account that earns interest. the value of the account can be represented as 25,000e^0.0198t, where t represents time, in years.

the time, t, in years that it will take for the account to have a value of $30,000 can be modeled as t=ln(k)/0.0198. what is the value of k?

  k = 1.2

Step-by-step explanation:

Solving for t when the account value is 30,000, we have ...

  30,000 = 25,000e^(0.0198t)

  30,000/25,000 = 1.2 = e^(0.0198t)

  ln(1.2) = 0.0198t

  t = ln(1.2)/0.0198

Matching this with the form ...

  t = ln(k)/0.0198

we see that k = 1.2.

k is the multiplier of account value in time period t.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2