Christopher works at the power plant for the southwest part of his home state. for peak operational performance, his department
employs 3 electricians for each generator and 4 inspectors for every 60 electricians. anthony, who works in the power plant for the
northwest part of the state, informs christopher that his department has 50 generators.
to maintain peak performance, how many inspectors will be required by the power plant in which anthony works?
a.
20 inspectors
b.
10 inspectors
c.
25 inspectors
d.
15 inspectors
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10: 49 am
11/24/2019

B) To maintain peak performance for every 50 generators, there are 10 inspectors.

Step-by-step explanation:

For peak operational:

3 electricians for each generator.  ⇒  1 Generator : 3 Electricians

4 inspectors for every 60 electricians. ⇒  60 Electricians : 4 Inspectors

Now, the number of generators the state has now = 50

Let us assume the number of  inspectors  required by the power plant  = m

Now, from the given ratios:

For, 3 electrician there  is 1 generator

⇒ For, 3 x 20 Electrician  there is 1  x 20 Generators.

or, for 60 Electrician there are 20 Generators.   (1)

Also, for 60 Electrician there are 4 inspectors.    (2)

⇒From (1) and (2), we get:

For every 20 generators, there are 4 inspectors.

And, from what we have assumed  For every 50 generators, there are m inspectors.

So, by the RATIO OF PROPORTION:

or, m = 10

Hence, to maintain peak performance for every 50 generators, there are 10 inspectors.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)