Write the expression 2a+b in the form of a fraction with the given denominator. check if the domain of the expression changed. if yes, state the changes explicitely.

3a

See below

Step-by-step explanation:

I will assume the given denominator is 3a as there is nothing attached to the statement.

Lets first look at the domain of 2a+b. As it is a polynomial with unknowns a and b, we know it has its domain in all real numbers for both  a and b as every polynomial does. For verifying it replace a and b by any real number you can think of.

Domain = a, b belonging to R

Now, if we divide 2a+b by 3a we will have:

(2a+b)/3a

As know we don not have a polynomial we cant state that the domain will still be all the real numbers for sure. We need to go further.

We have a fraction and as every fraction the denominator CAN'T be equal to 0, so 3a MUST be different to 0. This means that a MUST be different to 0. So, now our domain changes:

domain' = a, b belonging to R and a different to 0.

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

no ,sorry if you needed it but you can ask and try to see if any one will anwser ,

step-by-step explanation:

by good luck mark me as brainliest

have a nice day