Can anyone me solve this problem below:
3x2−5x−2
< 0
x2−9

and -3 < x < 3

Step-by-step explanation:

The inequality equation is  

3x² - 5x - 2 < 0

⇒ 3x² - 6x + x - 2 < 0

⇒ (x - 2)(3x + 1) < 0

Therefore, either (x - 2) > 0 and (3x + 1) < 0

⇒ x > 2 and which is not possible for any particular value of x.

or, (x - 2) < 0 and (3x + 1) > 0

⇒ x < 2 and which is valid.

So, the solution is (Answer)

Now, another inequality is  

x² - 9 < 0

⇒ x² < 9

Therefore, -3 < x < 3 is the solution. (Answer)

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

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