You roll a six-sided die. find the probability of each of the following scenarios: (a) rolling a 5 or a number greater than 3.
(b) rolling a number less than 4 or an even number.
(c) rolling a 4 or an odd number.

The probability of Rolling a 5 or a number greater than 3 is 0.5

The probability of Rolling a number less than 4 or an even number is 0.833

The probability of Rolling a 4 or an odd number is 0.667

Step-by-step explanation:

Consider the provided information.

You roll a six-sided die.

The number of possible outcomes are: S={1, 2, 3, 4, 5, 6}

Part (a) Rolling a 5 or a number greater than 3.

Number greater than 3 are 4, 5 and 6.

A = {4,5,6}

The required probability is:

The probability of Rolling a 5 or a number greater than 3 is 0.5

Part (b) Rolling a number less than 4 or an even number.

Less than 4: {1,2,3}

Even numbers: {2,4,6}

Rolling a number less than 4 or an even number: B={1,2,3,4,6}

The required probability is:

The probability of Rolling a number less than 4 or an even number is 0.833

Part (c) Rolling a 4 or an odd number.

Rolling a 4: {4}

Rolling an odd number: {1,3,5}

Rolling a 4 or an odd number: C={1,3,4,5}

The required probability is:

The probability of Rolling a 4 or an odd number is 0.667

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,