Find 3 consecutive even numbers where the product of the smaller two numbers is 64
less than the square of the largest number.

8,10 and 12

Step-by-step explanation:

The numbers are

(x-2)* (x-4)  = x^ -64

Diistributive

x^-4x-2x+8 = x^-64

Subtract x^ on both sides (It will be cancelled)

-6x+8 = -64

Subtract 8 on both sides

-6x=-72

Divide both sides by -6

x=12

12-2=10

12-4=8

 8*10=80                     12*12=144            144-80=64

80+64=144

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: