Take the laplace transform of the following initial value problem and solve for y(s)=l{y(t)}: y′′−2y′−24y=s(t)y(0)=0,y′(0)=0where s is a periodic function defined bys(t)={1,0,0≤t< 11≤t< 2, and s(t+2)=s(t) for all t≥0.hint: : use the formula for the laplace transform of a periodic function.