The lengths of three line segments are 4 centimeters, 5 centimeters, and 9 centimeters. using this information, triangles can be constructed.

No triangles can be constructed

Step-by-step explanation:

we know that

The Triangle Inequality Theorem, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

so

In this problem

------> is not true

therefore

No triangles can be constructed with the given side lengths

Well, technically yes. One can, but it would be a so-called "degenerate triangle".

-- The 4-cm and 5-cm sides are just exactly long enough to connect between the ends of the 9-cm side.  So they lie flat on top of it.

-- The angles at each end of the 9-cm side are both zero.

-- The angle at the vertex where the 4-cm side meets the 5-cm side is 180 degrees.

-- The sum of the angles in the triangle is 180 degrees.

-- The altitude of the triangle is zero.

-- The area of the triangle is zero.

-- When you look at the triangle, all you see is a 9-cm line segment.  The 4-cm and 5-cm line segments lie on top of it, so you don't see them.

-- You would say "There's no triangle there.".

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

i can't read the graph

step-by-step explanation: