In a recent poll, 600 people were asked if they liked soccer, and 72% said they did. based on this, construct a 99% confidence interval for the true population proportion of people who like soccer.

as in the reading, in your calculations:
--use z = 1.645 for a 90% confidence interval
--use z = 2 for a 95% confidence interval
--use z = 2.576 for a 99% confidence interval.

give your answers as decimals, to 4 decimal places.

out of 500 people sampled, 80 had kids. based on this, construct a 90% confidence interval for the true population proportion of people with kids.

as in the reading, in your calculations:
--use z = 1.645 for a 90% confidence interval
--use z = 2 for a 95% confidence interval
--use z = 2.576 for a 99% confidence interval.
give your answers to three decimals

give your answers as decimals, to three decimal places.

(0.6728, 0.7672)

(0.1330, 0.1870)

Step-by-step explanation:

Given that in a recent poll, 600 people were asked if they liked soccer, and 72% said they did.

Std error =

Margin of error for 99% we would use the value

Margin of error =

Confidence interval lower bound =

Upper bound =

99% confidence interval for the true population proportion of people who like soccer.=(0.6728, 0.7672)

b) n =500

Sample proportion p=

Margin of error for 90% =

90% confidence interval for the true population proportion of people with kids. =

where is the diagram? shown below where? ?

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100