Arocket is launched from a tower. the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.

equation:
y=-16x^2+153x+98

Step-by-step explanation:

Given the following Quadratic equation:

The steps to solve it are:

1. Substitute into the equation:

2. Use the Quadratic formula .

In this case:

Substituting values into the Quadratic equation, you get (Round the values to the nearest hundreth):

3. The positive value is the time that the rocket will hit the ground.

Therefore, the rocket will hit the ground after .

answer is because 4×10=40

and 98×4= is 392

40,392