Which of the following is a solution to 2cos^2x– 2 = 0 ?

a.0°
b.30°
c.180°
d.330°

A and C

Step-by-step explanation:

Given

2cos²x - 2 = 0 ( add 2 to both sides )

2cos²x = 2 ( divide both sides by 2 )

cos²x = 1 ( take the square root of both sides )

cos x = ± = ± 1

cos x = 1 ⇒ x = (1) = 0°

cos x  = - 1 ⇒ x = (- 1) = 180°

2 possible results

0° and 180°

Step-by-step explanation:

2cos² x– 2 = 0  (add 2 to both sides)

2cos² x = 2  (divide both sides by 2)

cos² x = 2/2

cos² x = 1

cos x = ±√1

cos x = ±1

because the range of x is not stated, there are 2 possible results for x  that will cause cos x to be either 1 or -1

0° and 180°

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

it would be:

c.parallelogram.