The perimeter of a rectangle field is 118m. if the length of the rectangle is 7m less than twice the width what is the length

Let:

P - perimeter

l - length

w - width

We know:

P = 118 m

l = 2w - 7

We replace the length with 2w - 7.

P = 2×(2w - 7) + 2w

118 = 4w - 14 + 2w

118 = 6w - 14

6w = 118 + 14

6w = 132

w = 22 meters

w = 22 l = 37

Explanation:

Perimeter = P

Length = l

Width = w

Formula: P = 2 ( w + l ) + 2w

We know

P = 118

l = 2w - 7

Solve

P = 2 (2w - 7) + 2w

118 = 4w - 14 + 2w

118 = 6w - 14

+14          +14

132 = 6w

 6       6

w = 22

2(22) - 7

44 - 7 = 37

l = 37

the answer to this question is 3/19

step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )