Find the linear approximation for f(x) = 12x3 + 3x2 + x + 2 at x= 1.

y = 43x − 25

Step-by-step explanation:

Evaluate the function at x=1:

f(x) = 12x³ + 3x² + x + 2

f(1) = 12 + 3 + 1 + 2

f(1) = 18

Find the slope of the tangent line at x=1:

f'(x) = 36x² + 6x + 1

f'(1) = 36 + 6 + 1

f'(1) = 43

Point-slope form:

y − y₀ = m (x − x₀)

y − 18 = 43 (x − 1)

Convert to slope-intercept form:

y − 18 = 43x − 43

y = 43x − 25

Graph:

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