Based on x with distribution indexed by θ ∈ ω, the problem is to test θ ∈ ω versus θ ∈ ω ? . suppose there exists a test φ such that e θ [φ(x)] ≤ β for all θ in ω, where β < α. show there exists a level α test φ ∗ (x) such that.

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

i dony know

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: