If y varies directly as x^2 and y = 72 when x =3, what is the value of y when x = 6?

288

Step-by-step explanation:

If y varies directly as x^2

i.e y varies directly as x * x

and y =72, when x =3

therefore, 72 = k* 3*3 9 (where k is constant)

72=k9

k = 72/9

=8

The value of y, when x =6 will be

y = 8 * 6^2

8*36 = 288

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

use formula for the circle a=3.14

step-by-step explanation: