(a) find the series' radius and interval of convergence. find the values of x for which the series converges

(b) absolutely and

(c) conditionally. summation from n equals 0 to infinity startfraction left parenthesis x minus 3 right parenthesis superscript n over 10 superscript n endfraction∑n=0[infinity] (x−3)n 10n(a) the radius of convergence is nothing. (simplify youranswer.) determine the interval of convergence. select the correct choice below and, if necessary, fill in the answer box to complete your choice.

a. the interval of convergence is nothing.(type a compound inequality. simplify your answer. use integers or fractions for any numbers in the expression.)

b. the series converges only at xequals= nothing. (type an integer or a simplified fraction.)

c. the series converges for all values of x.(b) for what values of x does the series converge absolutely?

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

a triangular prism is a 3 dimensional shape composed of triangles and rectangles. it is made from two triangular bases and three rectangular sides.  

answer: plz mark me brainliest

7 hours, 0 minutes, 0 seconds

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step-by-step explanation: