The sides of a rectangle are 25 cm and 8 cm. what is the measure, to the nearest degree, of the angle formed by the short side and a diagonal of the rectangle?

72°

Step-by-step explanation:

The lengths 25 cm and 8 cm are the sides of the rectangle.

See the attached diagram of rectangle ABCD.

Now, let us assume the diagonal AC makes x° angle with the shorter side BC i.e.∠ BCA = x°

So, using trigonometry we can write

⇒ degrees ≈ 72 degrees {Rounded to nearest degree} (Answer)

can you add an image ?

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3