Amarketing firm is asked to estimate the percent of existing customers who would purchase a "digital upgrade" to their basic cable tv service. the firm wants 99 percent confidence and an error of ± 5 percent. what is the required sample size (to the next higher integer)? a. 664b. 625c. 801d. 957

A. 664

Step-by-step explanation:

Given : A marketing firm is asked to estimate the percent of existing customers who would purchase a "digital upgrade" to their basic cable TV service.

But there is no information regarding the population proportion is mentioned.

Formula to find the samples size , if the prior estimate to the population proportion is unknown :

, where E = Margin of error.

z* = Two -tailed critical z-value

We know that critical value for 99% confidence interval =  [By z-table]

Margin of error = 0.05

Then, the minimum sample size would become :

Simplify,

Thus, the required sample size= 664

Hence, the correct answer is A. 664.

95.03 is the answer. hope this !

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step-by-step explanation: