If w is a subspace of r n , show that w ∩ w⊥ = {0}. hint: start from definition, no complicated computation, it’s just some simple logic. note that if u · u = 0, then u must be a zero vector. also, both w and w⊥ are vector spaces, hence {0} ⊂ w ∩ w⊥ is clear, you just need to show another inclusion.

afjnawenkfnjaw; enkanwelwaklalejjaw; fij

step-by-step explanation:

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

111

step-by-step explanation: