What are the dimensions of the lightest open-top right circular cylindrical can that will hold a volume of 2744 cmcubed3?

r=2.808cm    h = 100cm

then we get volume of cylinder that is 2744 As explained below

Step-by-step explanation:

Volume of cylinder = πr²h

Surface area of cylinder = 2πrh +πr²                                (1)

h= 2744 /πr²

put value oh h in equation (1)

Area =[2πr] 2744 /πr²

        =[5488/r +πr²]

dA/dx=0                                      

i.e     2πr=5488/r²

Solving this r.r= ∛5488/2π

                       =2.808

taking second derivation we get 100

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .