Ladonne has a budget of $240 for the new school clothes she need at least two new shirts pairs of pants and one pair of shoes the shirts cost $18 and the pants cost $32 each shoes cost $49 per pair plan two different combinations of number of shirts pants and shoes ladonne could to buy within her budget what's the total cost for each buying plan

LaDonne can buy 4 shirts, 2 pairs of pants, and 2 pair of shoes.

LaDonne can buy 5 shirts, 3 pairs of pants, and 1 pair of shoes.

Step-by-step explanation:

Consider the provided information.

LaDonne has a budget of $240 for the new school clothes.

She need at least two new shirts pairs of pants and one pair of shoes.

The shirts cost $18 and the Pants cost $32 each shoes cost $49 per pair.

We need to plan two different combinations of number of shirts pants and shoes.

Plan 1:

LaDonne could buy 4 shirts, $18×4=$72

2 pairs of pants,  $32×2=$64

2 pair of shoes for $49×2=$98

Total cost: $72+$64+$98=$234.

LaDonne can buy 4 shirts, 2 pairs of pants, and 2 pair of shoes.

Plan 2:

LaDonne could buy five shirts, $18×5=$90

Three pairs of pants,  $32×3=$96

One pair of shoes for $49

Total cost: $90+$96+$49=$235.

LaDonne can buy 5 shirts, 3 pairs of pants, and 1 pair of shoes.

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130