Can anyone me this? stuck with this problem for hours

p = 18.24 cm²

chance = 36.30%

Step-by-step explanation:

To solve this, you must find the area of both the square and the circle. Note that:

- one side of the square is 4√2 cm long.

- the radius of the circle is 4 cm long.

First, know the equation in how to solve for each area:

Area of Square: A = s² = side x side

Next, know the equation for the circle:

Area of Circle: A = πr²

plug in the corresponding numbers to the corresponding variables:

Area of square:

A = s²

s = 4√2

A = (4√2)² = 4√2 * 4√2 = 4 * 4 * √2 * √2  = 16 * 2 = 32

Your area of the square is 32 cm²

Area of circle:

A = πr²

r = 4

A = π(4)² = π(4 * 4) = π(16) = (3.14)(16) = 50.24

Your area of the circle is 50.24 cm²

Solve for the probability of the point landing in the white area by subtracting the total area of the circle with the area of the square:

50.24 - 32 = 18.24 cm²

p = 18.24 cm²

Now, to get the percentile chance of landing in the white area, divide the number gotten from total area:

18.24/50.24 = 0.3630 = 36.30%

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nlgqer

step-by-step

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90