How many ways are there to select 12 countries in the united nations to serve on a council if 5 are selected from a block of 45, 4 are selected from a block of 57, and the others are selected from the remaining 69 countries? briefly explain your answer.

There are 436937109262510348800 ways to selected 12 countries.

Step-by-step explanation:

Let the countries selected from the block of 45. For there are 45 options of countries to select. For there are 44 options of countries to select because there can be no repeated countries. With the same reasoning, for there are 43 options, for there are 42 options and for there are 41 options.

Let the countries selected from the block of 57 countries. For there are 57 options of countries to select. For there are 56 options of countries to select because there can be no repeated countries. With the same reasoning, for there are 55 options and for there are 54 options.

Let the countries selected from the block of 69 remain countries. For there are 69 options of countries to select. For there are 68 options of countries to select because there can be no repeated countries and for there are 67 options.

For find the total of options o ways to select 12 countries we multiply the above options.

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

answer is c

step-by-step explanation:

81/12=324/x

x=48