10 kids are randomly grouped into an a team with five kids and a b team with five kids. each grouping is equally likely.

(a) what is the size of the sample space?
(b) there are two kids in the group, alex and his best friend jose. what is the probability that alex and jose end up on the same team?

Our required probability is 0.44.

Step-by-step explanation:

Since we have given that

Number of kids in team A = 5

Number of kids in team B = 5

(a) What is the size of the sample space?

So, the size of sample space would be

(b) There are two kids in the group, Alex and his best friend Jose. What is the probability that Alex and Jose end up on the same team?

Number of ways that Alex and Jose does not end up on same team would be

Number of ways that Alex and Jose  end up on same team would be

252-140=112

So, the probability that Alex and Jose end up on the same team would be

Hence, our required probability is 0.44.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

50

step-by-step explanation: