(1 point) determine whether the given set is open, connected, and simply connected. for example, if it is open, connected, but not simply connected, type "yyn" standing for "yes, yes, no." a. {(x, y)|x> 1,y< 2} yyy b. {(x, y)|2x2+y2< 1} yyy c. {(x, y)|x2−y2< 1} nyy d. {(x, y)|x2−y2> 1} e. {(x, y)|1

5.25 ounces

step-by-step explanation:

divided 3/4 and 6

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)