Two pipes are connected to the same tank. when working together., they can fill the tank in 10hrs. the larger pipe, working alone, can fill the tank in 15 hrs less time than the smaller one. how long would the smaller one take, working alone, to fill the tank

30 hours

Step-by-step explanation:

Let the small pipe take time "t" to fill up the tank alone

Since larger pipe takes 15 HOURS LESS, so it will take "t - 15" time to fill up the tank alone

Let the whole tank be equal to "1" and each pipe fills up a fraction of the tank.

Smaller Pipe fills up 10/t, and

Larger Pipe fills up 10/(t-15)

Totalling "1". So we can write:

Now, we solve for t. First, we multiply whole equation by (t)(t-15), to get:

Now we multiply out and get a quadratic and solve by factoring. Shown below:

Since, this time is for the smaller pipe (which takes longer than 15 hours), so we disregard t = 5 and take t = 30 as our solution. So,

Smaller pipe takes 30 hours to fill up the tank alone

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3