Consider the function represented by the equation 6c = 2p – 10. write the equation in function notation, where c is the independent variable. f(c) = one-thirdp + five-thirds f(c) = 3c + 5 f(p) = one-thirdp + five-thirds f(p) = 3c + 5

f(c) = 3c + 5

Step-by-step explanation:

c is independent variable, p is dependent variable, so p = f(c)

6c = 2p -10

3c = p - 5

p = 3c + 5

f(c) = 3c + 5

F(c) = 3c +5  

Step-by-step explanation:

6c=2p-10

If c is considered to be as the independent variable, then p is the dependent variable

So we will clear and solve for variable p

6c = 2p-10

Dividing both sides by 2. We will have  

6c/2 = 2(p-5)/2

3c= p-5  

Adding 5 on both sides

3c+5= p

So p =3c+5

By writing the above equation in the functional notation form  

F(c) = 3c +5