Two angles are supplementary. the measure of the first angle is 10 degrees more than three times the second angle. find the measure of each angle

137.5° and 42.5°

Step-by-step explanation:

supplementary angles are two angles whose sum is equal to 180°.

Let the second angle be x then it is given that the first angle is 10 degrees more than 3 times second angle that is 3(x)+10°.

we know that the sum of first and second angles is 180° (supplementary angles)

so, (3(x)+10°)+(x) = 180°

                   4(x) = 170°

                       x = 170°/4 = 42.5°

so, first angle is 3(42.5°)+10° = 137.5°, second angle is x that is 42.5°

therefore, the angles are 137.5° and 42.5°.

12 servings. 4 times 3= 12

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)