Find three consecutive odd integers such that the sum of the first is two less than the second, and three more than the third is 70

9,11 and 13

Step-by-step explanation:

X+(x+2)+(x+4)= ?

3x+6=  ?

70/2=35      35-2=33

3x+6=33

3x=27

x=9

9+22+39=70

10 cm

step-by-step explanation:

if the polygon is a rectangle, then the perimeter is x+x+y+y. using the values that you gave, the perimeter is 3+3+2+2=10cm.

8 2/3 is the answer

step-by-step explanation: just use a calculator