8solid iron sphare with radius 'a cm' each are melted to form a sphare with radius 'b cm'. find the ratio of a: b

8 solid iron sphere with radius 'a cm' each are melted to form a sphere with radius 'b cm' then the ratio of a:b is 1 : 2

Solution:

Given that 8 solid iron sphere with radius 'a cm' each are melted to form a sphere with radius 'b cm'

Need to find the ratio of a:b

As 8 solid iron sphere with radius 'a cm' each are melted to form a sphere with radius 'b cm'.  

For sake of simplicity, let volume of 1 sphere of radius a cm is represented by and volume of 1 sphere of radius b cm is represented by

So volume of 8 solid iron sphere with radius 'a cm' = volume of  1 solid iron sphere with radius 'b cm'

 ---- eqn 1

Formula for volume of sphere is as follows:

Where r is radius of the sphere

Substituting r = a cm in the formula of volume of sphere we get

Substituting r = b cm in the formula of volume of sphere we get

a : b = 1 : 2

Hence the ratio of a:b is 1 : 2

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^