If f(x)= sin^−1 (x), then what is the value of f'(sqrt 3/ 2) in simplest form?

  2

Step-by-step explanation:

We can use the formula for the derivative of the arcsin function:

  f'(x) = 1/√(1 -x²)

Filling in x=(√3)/2, we get ...

  f'((√3)/2) = 1/√(1 -3/4) = 1/(1/2)

  f'((√3)/2) = 2

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