[50+25 points + the brainliest]

if sin θ = 3/5, and lies in quadrant ii, what are the exact values of sin 2θ, cos 2θ , and tan 2θ ?

you in advance!

sin2θ = -24/25

cos2θ = 7/25

tan2θ =  -24/7

Step-by-step explanation:

sinθ = 3/5

θ is in Quadrant II. So 2θ is in Quadrant III or IV. So sin2θ is negative. Nothing can be said about cos and tan yet.

sin135 = 0.707 > 3/5.

So θ > 135.

2θ lies in Quadrant IV. So cos2θ is positive and tan2θ is negative.

cosθ = √(1 - sin²θ)

        = -4/5

sin2θ = 2sinθcosθ = 2x(3/5)x(-4/5) = -24/25

cos2θ = 1 - 2sin²θ = 1 - 2x(3/5)² = 7/25

tan2θ = sin2θ/cos2θ = -24/7

muyb ajo

step-by-step explanation:

jegosu