Find all points having an x coordinate of 5 whose distance from the point (2,2) is 5.

(5,6) , (5,-2)

Step-by-step explanation:

Let the required point be P(5,y).

Its distance from (2,2) is 5 units.

So, + = 25.

So, +   = 25.

  9 +   = 25.

    = 16

    Two cases are possible for now

case 1 : y-2 = 4 .

            y = 6

required point will be (5,6)

case 2 : y - 2 = -4.

              y = -2.

required point will be (5,-2).

Two points are possible : (5,6) , (5,-2).

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

step-by-step explanation:

b and c