The length of the rectangle garden is three more than twice its width. if the perimeter of the garden is 114 feet, what is its width of the garden?

Dimensions of rectangular garden is: length = 39 feet and width = 18 feet

Given that length of the rectangle garden is three more than twice its width.

The perimeter of the garden is 114 feet

Need to determine width of the garden

Let assume width of the garden be represented by variable "x"

=>Twice of the width =

=> 3 more than Twice of the width= 3 + 2x = 2x + 3

As length of the rectangle garden is three more than twice its width ,

=> Length of the rectangle garden = 2x + 3  

Perimeter of the rectangle = 2( length + width)

=> Perimeter of the rectangular garden = 2 (Length of the rectangle garden + width of the garden)

= 2 (2x + 3 + x) = 2 (3x + 3 ) = 6x + 6

=> Perimeter of the rectangular garden = 6x + 6

As it is also given that Perimeter of the rectangular garden = 114 feet

=> 6x + 6 = 114 feet

=> 6x = 114 – 6

x = 18

Width of the garden = x = 18 feet

Length of the garden = = 2x + 3 = 2(18) + 3 = 39 feet

Hence dimensions of rectangular garden is length = 39 feet and width = 18 feet

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