50 points! a polynomial has been factored below, but some constants are missing. 2x^3 - 8x^2 - 24x = ax (x+b)(x+c) what are the missing values of a, b, and c?

In the given expression ,  

a = 2 , b = - 6 and c  = 4

Step-by-step explanation:

Here, the given polynomial is given as:

Now, to find the missing values of the constants a , b and c factorize the given polynomial.

We have:

or,

2 x (x - 6)(x + 4) = ax (x + b)(x + c)

Comparing the two given expressions, we get

2 x= a x

x + (- 6)  = x + b

x + c  = x + 4

⇒   a =2, b = - 6 and c  = 4

Hence, in the given expression ,  a =2, b = - 6 and c  = 4.

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4

0 is its x and y coordinate