Two numbers have these properties both numbers are greater than 6 the highest common factor is 6 the lowest common multiple is 60 find the two numbers

12 and 30 are two such given numbers.

Step-by-step explanation:

Here, given the LCM of both the numbers  = 60

The HCF of both the number = 6

Both number are greater then 6.

Now, as we know  LCM x HCF = Product of Two Numbers

⇒ 60 x 6 = 360 = Product of both numbers

Now, by the prime factorization of 360, we get:

360 =  2 x 2 x  2 x 3  x 3 x 5  = 12 x 30

Here, checking for the conditions:

(a) Both numbers 12 , 30 are greater than 6

(b)  HCF of 12 and 30  = 6

(c) LCM of 12 and 30 = 60

Hence, 12 and 30 are two such given numbers.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )