Sixty-four tickets are issued for a school
dance, and 96 brownies are ordered for
the refreshment table. each student gets
the same number of tickets as every
other student. each student also gets the
same number of brownies as every other
student.
each student will get — tickets and _
brownies.

Each students will get 3 tickets and 2 brownies  .

Step-by-step explanation:

Given as :

The total number of tickets issued for the school dance = 64

The number of brownies ordered for refreshment table = 96

Let the number of tickets given to each student = x

And The number of brownie given to each student = y

Now,

According to question

The tickets and brownies is distributed equally among students

So , Now, consider the tickets and brownies = n

Or, - = 1

Or, Taking LCM we get

= 1

Or, = 1

∴ n = 192

Now,

The number of tickets given to each student = x =

I.e x = 3

And The number of brownie given to each student = y =  

I.e y = 2

Hence Each students will get 3 tickets and 2 brownies  . Answer

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: