Suppose that n1(h) is an approximation to m for every h > 0 and that: m = n1(h) + k1h + k2h 2 + k3h 3 + . . for constants k1, k2, k3 . .. use the values n1(h), n1(h/3) and n1(h/9) to produce an o(h 3 ) approximation to m.

answer: the answer is e

step-by-step explanation:

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry

add -60 to 120 which will result in : 2x+3y=180

then subtract 2x: 3y=-2x+180

lastly, divide by 2: y= -2/3x+60

hope this is the answer you're looking for: )