Recall the equation for a circle with center ( h , k ) and radius r . at what point in the first quadrant does the line with equation y = x + 1 intersect the circle with radius 6 and center (0, 1)?

  (3√2, 1+3√2) ≈ (4.243, 5.243)

Step-by-step explanation:

The line has a slope of 1 and goes through the center of the circle, so will intersect the circle at the point ...

  (6, 6)/√2 +(0, 1) = (3√2, 1+3√2) ≈ (4.243, 5.243)

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0