In june 2008, chemical analysis of n1 =110 water samples from various parts of catawba river were made. in june 2012, the experiment was repeated using n2 = 85 water samples. we have the following result: chlorine content (2008) chlorine content (2012)latex: \overline{x_1}x1x1¯ = 17.8 latex: \overline{x_2}x2x2¯ = 18.3s1 = 1.8 s2 = 1.21. an environmental agency claims that the mean chlorine content in river increased from 2008 to 2012. choose the appropriate hypotheses to test the claima) latex: h_o\: ; \: \mu_1-\mu_2=0\: \: vs\: h_a\: ; \: \mu_1-\: \mu_2\: > 0b) latex: h_o; \: \mu_1-\mu_2=0\: \: vs\: \: h_a; \: \mu_1-\mu_2< 0c) latex: h_o; \: \mu_1-\mu_2=0\: \: vs\: \: \: h_a; \: \mu_1-\mu_2\ne02. the standardized test statistic is about3. find the rejection region at latex: \alpha = 0.054. compute the observed significance of the test.

Abarbecue sold 26 hamburgers and hot dogs. hamburgers sell for $3.50 each and hot dogs sell for $2.00 each. if the barbecue made $70 in sales, determine and state the number of hot dogs sold.

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.

Hi, can anyone show me how to do this problem? 100 points for this. in advance