Apair of standard dice is rolled find the probability that the sum of the two dice is greater than 12

Probability that the sum of the two dice is greater than 12 is ZERO.

Step-by-step explanation:

Here, when two dices are rolled together, the sample space is given as:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5,6)

(6, 1), (6, 2), (6, 3), (6, 4),(6,5), (6,6)  = Total 36 outcomes

Now, E :  Event of getting a  sum greater than 12.

So here, number of possible outcomes  = 0

So, the probability that the sum of the two dice is greater than 12  = 0/36  = 0

So, it is an IMPOSSIBLE EVENT.

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation: