Write the vector v in terms of i and j whose magnitude ||v|| and direction 0 are given. ||v|| = 4, 0 = 315 degree v= (type your answer in terms of i and j. type an exact answer using radicals as needed.

  v = 2√2i -2√2j

Step-by-step explanation:

  v = ||v||·cos(θ)i +||v||·sin(θ)j

  v = 4cos(315°)i +4sin(315°)j . . . . . . fill in the numbers

  v = 2√2i -2√2j . . . . . . . . . . . . . . . put in desired form

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.